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7x^2-62x+48=0
a = 7; b = -62; c = +48;
Δ = b2-4ac
Δ = -622-4·7·48
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-50}{2*7}=\frac{12}{14} =6/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+50}{2*7}=\frac{112}{14} =8 $
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